What is -(-4)^2-4(-4)+5 ?

The solution to -(-4)^2-4(-4)+5 is 5

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-(-4)^2-4(-4)+5

- (- 4)^{2} - 4 (- 4) + 5

5

Solution steps

- (- 4)^{2} - 4 (- 4) + 5

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= - 16 - 4 (- 4) + 5

Multiply and divide (left to right)

4 (- 4) : - 16

4 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 4) = - 4 \cdot 4 = - 16

= - 16

= - 16 - (- 16) + 5

Add and subtract (left to right)

- 16 - (- 16) + 5 : 5

- 16 - (- 16) + 5

Apply rule

- (- a) = + a

- (- 16) = + 16

= - 16 + 16 + 5

- 16 + 16 = 0

= 0 + 5

0 + 5 = 5

= 5

= 5

- 3 \times (- 3) - ((- 1)^{2} - 2)^{3}

\frac{1 + 4 ( 8 ) + 9}{6}

\frac{3 ^{2} - 36}{3 - 6}

(- 4)^{2} + 4 (- 4) - 5

(- 4)^{2} + 4 (- 4) + 3