What is (-3)^2+2(-3) ?

The solution to (-3)^2+2(-3) is 3

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(-3)^2+2(-3)

(- 3)^{2} + 2 (- 3)

3

Solution steps

(- 3)^{2} + 2 (- 3)

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 + 2 (- 3)

Multiply and divide (left to right)

2 (- 3) : - 6

2 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 3) = - 2 \cdot 3 = - 6

= - 6

= 9 - 6

Add and subtract (left to right)

9 - 6 : 3

9 - 6

9 - 6 = 3

= 3

= 3

35 - \frac{1}{8} - \frac{3}{24}

19 \times 5 + 27 \div 3 - 3^{2}

(5^{2} - 3^{2}) \div 4 - (1 + 2^{0} + 3^{0})

(- 4) (4 - 2)

(50 - 2) \div 4 - 4^{2}