How do you solve inequalities with absolute value bars?

To solve an inequality that contains absolute value bars isolate the absolute value expression on one side of the inequality. Then, divide the inequality into two separate cases, one for each possible value of the absolute value expression, positive or negative, and solve each case separately.

What does absolute value inequality mean in math?

An absolute value inequality is an inequality that involves an absolute value expression.

What is the difference between and and or in an absolute inequality?

In an absolute value inequality, 'and' and 'or' are used to combine the solutions of two inequalities. When 'and' is used, both inequalities must be satisfied for the solution to be valid. When 'or' is used, at least one of the inequalities must be satisfied for the solution to be valid.

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x^2	x^{\msquare}	\log_{\msquare}	\sqrt{\square}	\nthroot[\msquare]{\square}	\le	\ge	\frac{\msquare}{\msquare}	\cdot	\div	x^{\circ}	\pi
\left(\square\right)^{'}	\frac{d}{dx}	\frac{\partial}{\partial x}	\int	\int_{\msquare}^{\msquare}	\lim	\sum	\infty	\theta	(f\:\circ\:g)	f(x)

\mathrm{simplify} \mathrm{solve\:for} \mathrm{expand} \mathrm{factor} \mathrm{rationalize}

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Frequently Asked Questions (FAQ)

How do you solve inequalities with absolute value bars?
To solve an inequality that contains absolute value bars isolate the absolute value expression on one side of the inequality. Then, divide the inequality into two separate cases, one for each possible value of the absolute value expression, positive or negative, and solve each case separately.
What does absolute value inequality mean in math?
An absolute value inequality is an inequality that involves an absolute value expression.
What is the difference between and and or in an absolute inequality?
In an absolute value inequality, 'and' and 'or' are used to combine the solutions of two inequalities. When 'and' is used, both inequalities must be satisfied for the solution to be valid. When 'or' is used, at least one of the inequalities must be satisfied for the solution to be valid.

- \twostack{▭}{▭}	\lt	7	8	9	\div	AC
+ \twostack{▭}{▭}	\gt	4	5	6	\times	\square\frac{\square}{\square}
\times \twostack{▭}{▭}	\left(	1	2	3	-	x
▭\:\longdivision{▭}	\right)	.	0	=	+	y

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