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derivative of (\frac{5x+2/(7x)}{2x})

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ddx (5x+27x 2x )

Solution

−5x−414x³

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ddx (5x+27x 2x )

Take the constant out: (a·f)′=a·f ′

=17 2 ddx (5x+2x x )

Apply the Quotient Rule: (fg )^′=f ′·g−g′·fg²

=17 2 · ddx (5x+2x )x−dxdx 5x+2x x²

ddx (5x+2x )=−2x²

dxdx =1

=17 2 · (−2x² )x−1· 5x+2x x²

Simplify 17 2 · (−2x² )x−1· 5x+2x x² : −5x−414x³

=−5x−414x³

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
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derivative of (\frac{5x+2/(7x)}{2x})

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