What are the solutions to the equation x^2+6x+10=-x ?

The solutions to the equation x^2+6x+10=-x are x=-2,x=-5

Find the zeros of x^2+6x+10=-x

The zeros of x^2+6x+10=-x are x=-2,x=-5

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x^{2} + 6 x + 10 = - x

x = - 2, x = - 5

Solution steps

x^{2} + 6 x + 10 = - x

Move

x

to the left side

x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 1}, x_{2} = \frac{- 7 - 3}{2 \cdot 1}

x = \frac{- 7 + 3}{2 \cdot 1} : - 2

x = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

2 x^{2} - 20 x + 41

\frac{x ^{2} - 4}{3} - \frac{6 - x}{2} = 3

a^{2} + (- 2 a)^{2} = 4 0^{2}

2 x^{2} - 20 x + 41 = 0

a x^{2}

What are the solutions to the equation x^2+6x+10=-x ?
The solutions to the equation x^2+6x+10=-x are x=-2,x=-5
Find the zeros of x^2+6x+10=-x
The zeros of x^2+6x+10=-x are x=-2,x=-5