What are the solutions to the equation -4x^2+20x=25 ?

The solutions to the equation -4x^2+20x=25 are x= 5/2

Find the zeros of -4x^2+20x=25

The zeros of -4x^2+20x=25 are x= 5/2

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- 4 x^{2} + 20 x = 25

x = \frac{5}{2}

Decimal

x = 2.5

Solution steps

- 4 x^{2} + 20 x = 25

Move

25

to the left side

- 4 x^{2} + 20 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 4 ) ( - 25 )}{2 ( - 4 )}

2 0^{2} - 4 (- 4) (- 25) = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 ( - 4 )}

x = \frac{- 20}{2 ( - 4 )}

\frac{- 20}{2 ( - 4 )} = \frac{5}{2}

x = \frac{5}{2}

The solution to the quadratic equation is:

x = \frac{5}{2}

2 x^{2} + 15 x + 27 = 0

t, 15 = 11.11 + 6 t^{2}

x^{2} - 4 x - 5

30.252 x^{2} - 1290 x + 2946.667 = 0

y, 2 x^{2} + x y + y^{2} = 4

What are the solutions to the equation -4x^2+20x=25 ?
The solutions to the equation -4x^2+20x=25 are x= 5/2
Find the zeros of -4x^2+20x=25
The zeros of -4x^2+20x=25 are x= 5/2