x^2+(bx)/a =-c/a

解

x^{2} + \frac{b x}{a} = - \frac{c}{a}

x = \frac{- b + b ^{2} - 4 a c}{2 a}, x = \frac{- b - b ^{2} - 4 a c}{2 a}; a \neq = 0

解答ステップ

x^{2} + \frac{b x}{a} = - \frac{c}{a}

以下で両辺を乗じる:

a

a x^{2} + b x = - c; a \neq = 0

c

を左側に移動します

a x^{2} + b x + c = 0; a \neq = 0

解くとthe二次式

x_{1, 2} = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{- b + b ^{2} - 4 a c}{2 a}; a \neq = 0

x = \frac{- b - b ^{2} - 4 a c}{2 a}; a \neq = 0

二次equationの解:

x = \frac{- b + b ^{2} - 4 a c}{2 a}, x = \frac{- b - b ^{2} - 4 a c}{2 a}; a \neq = 0