What are the solutions to the equation 16x-8=9x^2-9x-108 ?

The solutions to the equation 16x-8=9x^2-9x-108 are x=5,x=-20/9

Find the zeros of 16x-8=9x^2-9x-108

The zeros of 16x-8=9x^2-9x-108 are x=5,x=-20/9

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16 x - 8 = 9 x^{2} - 9 x - 108

x = 5, x = - \frac{20}{9}

Decimal

x = 5, x = - 2.22222 \dots

Solution steps

16 x - 8 = 9 x^{2} - 9 x - 108

Switch sides

9 x^{2} - 9 x - 108 = 16 x - 8

Move

8

to the left side

9 x^{2} - 9 x - 100 = 16 x

Move

16 x

to the left side

9 x^{2} - 25 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 9 ( - 100 )}{2 \cdot 9}

(- 25)^{2} - 4 \cdot 9 (- 100) = 65

x_{1, 2} = \frac{- ( - 25 ) \pm 65}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 65}{2 \cdot 9}, x_{2} = \frac{- ( - 25 ) - 65}{2 \cdot 9}

x = \frac{- ( - 25 ) + 65}{2 \cdot 9} : 5

x = \frac{- ( - 25 ) - 65}{2 \cdot 9} : - \frac{20}{9}

The solutions to the quadratic equation are:

x = 5, x = - \frac{20}{9}

4 d^{2} + 2 d - 2 = 3 d

81 x^{2} + 198 x + 121 = 0

v, F = \frac{m v ^{2}}{r ^{2}}

3 + x = x^{2} + 3 x

x^{2} + 2 x + 17

What are the solutions to the equation 16x-8=9x^2-9x-108 ?
The solutions to the equation 16x-8=9x^2-9x-108 are x=5,x=-20/9
Find the zeros of 16x-8=9x^2-9x-108
The zeros of 16x-8=9x^2-9x-108 are x=5,x=-20/9