What are the solutions to the equation x^2-5x+17=11 ?

The solutions to the equation x^2-5x+17=11 are x=3,x=2

Find the zeros of x^2-5x+17=11

The zeros of x^2-5x+17=11 are x=3,x=2

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x^{2} - 5 x + 17 = 11

x = 3, x = 2

Solution steps

x^{2} - 5 x + 17 = 11

Move

11

to the left side

x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

x = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

x = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

3 x^{2} - 32 x + 69 = 0

2 n^{2} - 9 n + 5 = 2 n

x^{2} + 4 x - 21 = 0

2 x^{2} + 12 x + 8

6 w^{2} - 26 w + 5 = w^{2}

What are the solutions to the equation x^2-5x+17=11 ?
The solutions to the equation x^2-5x+17=11 are x=3,x=2
Find the zeros of x^2-5x+17=11
The zeros of x^2-5x+17=11 are x=3,x=2