What are the solutions to the equation k^2+5k-3=0 ?

The solutions to the equation k^2+5k-3=0 are k=(-5+sqrt(37))/2 ,k=(-5-sqrt(37))/2

Find the zeros of k^2+5k-3=0

The zeros of k^2+5k-3=0 are k=(-5+sqrt(37))/2 ,k=(-5-sqrt(37))/2

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k^{2} + 5 k - 3 = 0

k = \frac{- 5 + 37}{2}, k = \frac{- 5 - 37}{2}

Decimal

k = 0.54138 \dots, k = - 5.54138 \dots

Solution steps

k^{2} + 5 k - 3 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 3) = 37

k_{1, 2} = \frac{- 5 \pm 37}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 5 + 37}{2 \cdot 1}, k_{2} = \frac{- 5 - 37}{2 \cdot 1}

k = \frac{- 5 + 37}{2 \cdot 1} : \frac{- 5 + 37}{2}

k = \frac{- 5 - 37}{2 \cdot 1} : \frac{- 5 - 37}{2}

The solutions to the quadratic equation are:

k = \frac{- 5 + 37}{2}, k = \frac{- 5 - 37}{2}

7 x^{2} = 56

2 x^{2} + 10 x - 16 = 0

3 x^{2} - 6 x + 80 = - 4

5 (3 x - 2)^{2} + 27 = 32

(x 3)^{2} + x^{2} = 1

What are the solutions to the equation k^2+5k-3=0 ?
The solutions to the equation k^2+5k-3=0 are k=(-5+sqrt(37))/2 ,k=(-5-sqrt(37))/2
Find the zeros of k^2+5k-3=0
The zeros of k^2+5k-3=0 are k=(-5+sqrt(37))/2 ,k=(-5-sqrt(37))/2