What are the solutions to the equation 3x^2-6x+80=-4 ?

The solutions to the equation 3x^2-6x+80=-4 are x=1+3sqrt(3)i,x=1-3sqrt(3)i

Find the zeros of 3x^2-6x+80=-4

The zeros of 3x^2-6x+80=-4 are x=1+3sqrt(3)i,x=1-3sqrt(3)i

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3 x^{2} - 6 x + 80 = - 4

x = 1 + 33 i, x = 1 - 33 i

Solution steps

3 x^{2} - 6 x + 80 = - 4

Move

4

to the left side

3 x^{2} - 6 x + 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 84}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 84 : 183 i

x_{1, 2} = \frac{- ( - 6 ) \pm 18 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 18 3 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 18 3 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 18 3 i}{2 \cdot 3} : 1 + 33 i

x = \frac{- ( - 6 ) - 18 3 i}{2 \cdot 3} : 1 - 33 i

The solutions to the quadratic equation are:

x = 1 + 33 i, x = 1 - 33 i

5 (3 x - 2)^{2} + 27 = 32

(x 3)^{2} + x^{2} = 1

4 y^{2} = - 12 y - 9

x^{2} = - 9 x - 20

19.25 = - 8.5 (2 r - 1.75)^{2}

What are the solutions to the equation 3x^2-6x+80=-4 ?
The solutions to the equation 3x^2-6x+80=-4 are x=1+3sqrt(3)i,x=1-3sqrt(3)i
Find the zeros of 3x^2-6x+80=-4
The zeros of 3x^2-6x+80=-4 are x=1+3sqrt(3)i,x=1-3sqrt(3)i