What are the solutions to the equation 16=x^2-10x+25 ?

The solutions to the equation 16=x^2-10x+25 are x=9,x=1

Find the zeros of 16=x^2-10x+25

The zeros of 16=x^2-10x+25 are x=9,x=1

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16 = x^{2} - 10 x + 25

x = 9, x = 1

Solution steps

16 = x^{2} - 10 x + 25

Switch sides

x^{2} - 10 x + 25 = 16

Move

16

to the left side

x^{2} - 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 9 = 8

x_{1, 2} = \frac{- ( - 10 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 8}{2 \cdot 1}

x = \frac{- ( - 10 ) + 8}{2 \cdot 1} : 9

x = \frac{- ( - 10 ) - 8}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 9, x = 1

6 x^{2} + 108 x = - 582

(x - 10) (x + 7) = 0

4 x^{2} = 18

x^{2} + 5 x + 25

4 (10 - 5 x)^{2} = 49

What are the solutions to the equation 16=x^2-10x+25 ?
The solutions to the equation 16=x^2-10x+25 are x=9,x=1
Find the zeros of 16=x^2-10x+25
The zeros of 16=x^2-10x+25 are x=9,x=1