What is the answer to -1=(x^2+1)/(x-3) ?

The answer to -1=(x^2+1)/(x-3) is x=1,x=-2

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-1=(x^2+1)/(x-3)

- 1 = \frac{x ^{2} + 1}{x - 3}

x = 1, x = - 2

Solution steps

- 1 = \frac{x ^{2} + 1}{x - 3}

Multiply both sides by

x - 3

- (x - 3) = x^{2} + 1

Solve

- (x - 3) = x^{2} + 1 : x = 1, x = - 2

x = 1, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 3

Combine undefined points with solutions:

x = 1, x = - 2

\frac{1}{x} + 2 = \frac{1}{x ^{2} + x}

\frac{6 - 5 + 14}{n \cdot 2} = 15

\frac{5}{3 x - 8} = - 1

q + \frac{9}{q} = - 10

1 + \frac{3}{x - 5} = \frac{3}{x ^{2} - 9 x + 20}

What is the answer to -1=(x^2+1)/(x-3) ?
The answer to -1=(x^2+1)/(x-3) is x=1,x=-2
Solve for x: -1=(x^2+1)/(x-3)
The solution is x=1,x=-2