What is the answer to 49^{x+1}=(1/7)^x ?

The answer to 49^{x+1}=(1/7)^x is x=-2/3

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49^{x+1}=(1/7)^x

4 9^{x + 1} = (\frac{1}{7})^{x}

x = - \frac{2}{3}

Decimal

x = - 0.66666 \dots

Solution steps

4 9^{x + 1} = (\frac{1}{7})^{x}

Apply exponent rules

2 (x + 1) = - x

Solve

2 (x + 1) = - x : x = - \frac{2}{3}

x = - \frac{2}{3}

4 \cdot 5^{x} + 25 = 5^{x + 1} - 4 \cdot 5^{x - 1}

e^{x + 1} - 2^{3 - x} = 0

9^{2 x - 4} = 2 7^{x - 1}

91500 = 100000 - 272000 (\frac{1}{2})^{x}

- 4.5 e^{- 0.3 x} + 9 e^{- 0.6 x} = 0

What is the answer to 49^{x+1}=(1/7)^x ?
The answer to 49^{x+1}=(1/7)^x is x=-2/3
Solve for x: 49^{x+1}=(1/7)^x
The solution is x=-2/3