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Popular >

e^{x+1}-2^{3-x}=0

Solution

e^{x + 1} - 2^{3 - x} = 0

Solution

x = \frac{3 ln ( 2 ) - 1}{1 + ln ( 2 )}

+1

Decimal

x = 0.63753 \dots

Solution steps

e^{x + 1} - 2^{3 - x} = 0

Add

2^{3 - x}

to both sides

e^{x + 1} - 2^{3 - x} + 2^{3 - x} = 0 + 2^{3 - x}

Simplify

e^{x + 1} = 2^{3 - x}

Apply exponent rules

x + 1 = (3 - x) ln (2)

Solve

x + 1 = (3 - x) ln (2) : x = \frac{3 ln ( 2 ) - 1}{1 + ln ( 2 )}

x = \frac{3 ln ( 2 ) - 1}{1 + ln ( 2 )}

Graph

Popular Examples

9^{2x-4}=27^{x-1}

9^{2 x - 4} = 2 7^{x - 1}

91500=100000-272000(1/2)^x

91500 = 100000 - 272000 (\frac{1}{2})^{x}

-4.5e^{-0.3x}+9e^{-0.6x}=0

- 4.5 e^{- 0.3 x} + 9 e^{- 0.6 x} = 0

5 e^{- 3 x} - 4 = 6

1/(81^{(x-2))}=27^{(1-x)}

\frac{1}{8 1 ^{(x - 2)}} = 2 7^{(1 - x)}

Frequently Asked Questions (FAQ)

What is the answer to e^{x+1}-2^{3-x}=0 ?
The answer to e^{x+1}-2^{3-x}=0 is x=(3ln(2)-1)/(1+ln(2))