What are the solutions to the equation roots x^3+x^2+4x+4 ?

The solutions to the equation roots x^3+x^2+4x+4 are x=-1,x=2i,x=-2i

Find the zeros of roots x^3+x^2+4x+4

The zeros of roots x^3+x^2+4x+4 are x=-1,x=2i,x=-2i

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roots

x^{3} + x^{2} + 4 x + 4

x = - 1, x = 2 i, x = - 2 i

Solution steps

x^{3} + x^{2} + 4 x + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + x^{2} + 4 x + 4 = 0

Factor

x^{3} + x^{2} + 4 x + 4 : (x + 1) (x^{2} + 4)

(x + 1) (x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} + 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = - 1, x = 2 i, x = - 2 i

x^{5} = 18 x^{3} - 81 x

m^{5} + 5 m^{4} - 2 m^{3} - 10 m^{2} + m + 5 = 0

(x - 1)^{4} - (x - 1)^{2} - 12 = 0

x, (x^{2} + y^{2})^{3} = y^{4}

x (x - 3) (x - 2) = 72

What are the solutions to the equation roots x^3+x^2+4x+4 ?
The solutions to the equation roots x^3+x^2+4x+4 are x=-1,x=2i,x=-2i
Find the zeros of roots x^3+x^2+4x+4
The zeros of roots x^3+x^2+4x+4 are x=-1,x=2i,x=-2i