What are the solutions to the equation c^3=27 ?

The solutions to the equation c^3=27 are c=3,c=-3/2+(3sqrt(3))/2 i,c=-3/2-(3sqrt(3))/2 i

Find the zeros of c^3=27

The zeros of c^3=27 are c=3,c=-3/2+(3sqrt(3))/2 i,c=-3/2-(3sqrt(3))/2 i

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c^{3} = 27

c = 3, c = - \frac{3}{2} + \frac{3 3}{2} i, c = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

c^{3} = 27

For

x^{3} = f (a)

the solutions are

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

c = 327, c = 327 \frac{- 1 + 3 i}{2}, c = 327 \frac{- 1 - 3 i}{2}

327 = 3

Simplify

327 \frac{- 1 + 3 i}{2} : - \frac{3}{2} + \frac{3 3}{2} i

Simplify

327 \frac{- 1 - 3 i}{2} : - \frac{3}{2} - \frac{3 3}{2} i

c = 3, c = - \frac{3}{2} + \frac{3 3}{2} i, c = - \frac{3}{2} - \frac{3 3}{2} i

6 x^{3} - 35 x^{2} + 26 x - 5 = 0

480 = \frac{4}{3} π r^{3}

r^{4} - r = 0

y^{4} + 2 y^{3} + y^{2} + 8 y - 12 = 0

2 x^{3} - 5 x^{2} - 4 x + 3

What are the solutions to the equation c^3=27 ?
The solutions to the equation c^3=27 are c=3,c=-3/2+(3sqrt(3))/2 i,c=-3/2-(3sqrt(3))/2 i
Find the zeros of c^3=27
The zeros of c^3=27 are c=3,c=-3/2+(3sqrt(3))/2 i,c=-3/2-(3sqrt(3))/2 i