What is (\partial)/(\partial y)(sin(x)cos(y)) ?

The answer to (\partial)/(\partial y)(sin(x)cos(y)) is -sin(x)sin(y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(sin(x)cos(y))

\frac{\partial}{\partial y} (sin (x) cos (y))

- sin (x) sin (y)

Solution steps

\frac{\partial}{\partial y} (sin (x) cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (x) \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= sin (x) (- sin (y))

Simplify

= - sin (x) sin (y)

\frac{d}{d x} (\frac{3}{x ^{2} + 2})

\frac{d}{d x} (x - 2 y + 2 z)

\int \frac{3}{1 + x ^{2}} d x

\frac{1}{( s - 1 ) ^{2} + 1}

f (x) = csc (x), at x = \frac{π}{6}

What is (\partial)/(\partial y)(sin(x)cos(y)) ?
The answer to (\partial)/(\partial y)(sin(x)cos(y)) is -sin(x)sin(y)