What is the integral of sin(x)-2cos(x) ?

The integral of sin(x)-2cos(x) is -cos(x)-2sin(x)+C

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integral of sin(x)-2cos(x)

\int sin (x) - 2 cos (x) d x

- cos (x) - 2 sin (x) + C

Solution steps

\int sin (x) - 2 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (x) d x - \int 2 cos (x) d x

\int sin (x) d x = - cos (x)

\int 2 cos (x) d x = 2 sin (x)

= - cos (x) - 2 sin (x)

Add a constant to the solution

= - cos (x) - 2 sin (x) + C

\int \frac{72}{x ^{2} 4 x ^{2} + 9} d x

n = 0 \sum \infty (5 x)^{n}

\frac{1}{1 - x ^{2}}

y = x, (4, 2)

\frac{d}{d x} (3 x^{2} + 12 x + 9)

What is the integral of sin(x)-2cos(x) ?
The integral of sin(x)-2cos(x) is -cos(x)-2sin(x)+C