What is the tangent of y=sqrt(x),(4,2) ?

The tangent of y=sqrt(x),(4,2) is y= 1/4 x+1

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tangent of y=sqrt(x),(4,2)

tangent of

y = x, (4, 2)

y = \frac{1}{4} x + 1

Solution steps

Find the slope of

y = x : \frac{d y}{d x} = \frac{1}{2 x}

Compute the slope of

y = x

(4, 2) : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(4, 2) : y = \frac{1}{4} x + 1

y = \frac{1}{4} x + 1

\frac{d}{d x} (3 x^{2} + 12 x + 9)

\int \frac{1}{36 e ^{- 5 x} + e ^{5 x}} d x

(4) (8.8)

\int 9 (9 x + 2) d x

sin (2 x), 0.0001

What is the tangent of y=sqrt(x),(4,2) ?
The tangent of y=sqrt(x),(4,2) is y= 1/4 x+1