What is the solution for (dy)/(dx)=(y^2)/(x-1) ?

The solution for (dy)/(dx)=(y^2)/(x-1) is y=-1/(ln(-1+x)+c_{1)}

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(dy)/(dx)=(y^2)/(x-1)

\frac{d y}{d x} = \frac{y ^{2}}{x - 1}

y = - \frac{1}{ln ( - 1 + x ) + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{y ^{2}}{x - 1}

Solve separable ODE:

y = - \frac{1}{ln ( - 1 + x ) + c _{1}}

y = - \frac{1}{ln ( - 1 + x ) + c _{1}}

\frac{\partial}{\partial y} (x^{2} - 3 x y + y^{2})

f (x) = 2 x^{2} - x

\int \frac{1}{t ^{2} - 2 t + 26} d t

y^{^{'}} + y^{2} = 0

\int_{\frac{1}{2}}^{5} 12 x ln (2 x) d x

What is the solution for (dy)/(dx)=(y^2)/(x-1) ?
The solution for (dy)/(dx)=(y^2)/(x-1) is y=-1/(ln(-1+x)+c_{1)}