What is the solution for (dy)/(dt)=y+1+2sin(t) ?

The solution for (dy)/(dt)=y+1+2sin(t) is y=-1-cos(t)-sin(t)+c_{1}e^t

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(dy)/(dt)=y+1+2sin(t)

\frac{d y}{d t} = y + 1 + 2 sin (t)

y = - 1 - cos (t) - sin (t) + c_{1} e^{t}

Solution steps

\frac{d y}{d t} = y + 1 + 2 sin (t)

Solve linear ODE:

y = - 1 - cos (t) - sin (t) + c_{1} e^{t}

y = - 1 - cos (t) - sin (t) + c_{1} e^{t}

\frac{\partial}{\partial z} (x^{2} y cos (\frac{z}{t}))

\int 1 - (x - 1)^{2} d x

\frac{d}{d x} (x^{3} - 12 x + 1)

n = 1 \sum \infty (- 0.2)^{n}

2 cos (2 t + \frac{π}{6})

What is the solution for (dy)/(dt)=y+1+2sin(t) ?
The solution for (dy)/(dt)=y+1+2sin(t) is y=-1-cos(t)-sin(t)+c_{1}e^t