What is laplacetransform 2cos(2t+pi/6) ?

The answer to laplacetransform 2cos(2t+pi/6) is (sqrt(3)s-2)/(s^2+4)

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laplacetransform 2cos(2t+pi/6)

laplace transform

2 cos (2 t + \frac{π}{6})

\frac{3 s - 2}{s ^{2} + 4}

Solution steps

L {2 cos (2 t + \frac{π}{6})}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {cos (2 t + \frac{π}{6})}

L {cos (2 t + \frac{π}{6})} : \frac{3 s - 2}{2 ( s ^{2} + 4 )}

= 2 \cdot \frac{3 s - 2}{2 ( s ^{2} + 4 )}

Refine

2 \frac{3 s - 2}{2 ( s ^{2} + 4 )} : \frac{3 s - 2}{s ^{2} + 4}

= \frac{3 s - 2}{s ^{2} + 4}

f (x) =, x at x

f (x) = x + 7

x \to - 3 - lim (\frac{x + 2}{x + 3})

\int 2 x - x^{2} d x

y = 50 - x^{2}

What is laplacetransform 2cos(2t+pi/6) ?
The answer to laplacetransform 2cos(2t+pi/6) is (sqrt(3)s-2)/(s^2+4)