What is the sum from n=1 to infinity of (-0.2)^n ?

The sum from n=1 to infinity of (-0.2)^n is converges

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sum from n=1 to infinity of (-0.2)^n

n = 1 \sum \infty (- 0.2)^{n}

converges

Solution steps

n = 1 \sum \infty (- 0.2)^{n}

Apply Series Ratio Test:

converges

= converges

2 cos (2 t + \frac{π}{6})

f (x) =, x at x

f (x) = x + 7

x \to - 3 - lim (\frac{x + 2}{x + 3})

\int 2 x - x^{2} d x

What is the sum from n=1 to infinity of (-0.2)^n ?
The sum from n=1 to infinity of (-0.2)^n is converges