What is the solution for e^xy*y^'=e^{-y}+e^{-2x-y} ?

The solution for e^xy*y^'=e^{-y}+e^{-2x-y} is y=\W((-3/(e^x)-1/(e^{3x)}+c_{1})/(3e))+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

e^xy*y^'=e^{-y}+e^{-2x-y}

e^{x} y \cdot y^{^{'}} = e^{- y} + e^{- 2 x - y}

y = W (\frac{- \frac{3}{e ^{x}} - \frac{1}{e ^{3 x}} + c _{1}}{3 e}) + 1

Solution steps

e^{x} y \cdot y^{'} (x) = e^{- y} + e^{- 2 x - y}

Solve separable ODE:

y = W (\frac{- \frac{3}{e ^{x}} - \frac{1}{e ^{3 x}} + c _{1}}{3 e}) + 1

y = W (\frac{- \frac{3}{e ^{x}} - \frac{1}{e ^{3 x}} + c _{1}}{3 e}) + 1

f (x) = sin (2 x), - \frac{π}{2}, \frac{π}{6}

\frac{d ^{2}}{d x ^{2}} (11 e^{x^{2}})

(- 1 x - 2)^{10}

- 204 x

\frac{d}{d x} (x^{2} - 2 x + 1)

What is the solution for e^xy*y^'=e^{-y}+e^{-2x-y} ?
The solution for e^xy*y^'=e^{-y}+e^{-2x-y} is y=\W((-3/(e^x)-1/(e^{3x)}+c_{1})/(3e))+1