What is the integral from 0 to 0.08 of 2000x ?

The integral from 0 to 0.08 of 2000x is 6.4

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integral from 0 to 0.08 of 2000x

\int_{0}^{0.08} 2000 x d x

6.4

Solution steps

\int_{0}^{0.08} 2000 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2000 \cdot \int_{0}^{0.08} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.08}

= 2000 [\frac{x ^{2}}{2}]_{0}^{0.08}

Simplify

= 2000 [0.5 x^{2}]_{0}^{0.08}

Compute the boundaries:

0.0032

= 2000 \cdot 0.0032

Simplify

= 6.4

\frac{d}{d x} (\frac{2 x}{x + 2})

\int 2 + 2 sin (x) d x

y = 4 x sin (x), (\frac{π}{2}, 2 π)

(x y + 2 y) d x + (3 x) d y = 0

x^{2} + 3 x

What is the integral from 0 to 0.08 of 2000x ?
The integral from 0 to 0.08 of 2000x is 6.4