What is the derivative of (3x-2^2) ?

The derivative of (3x-2^2) is 6(3x-2)

What is the first derivative of (3x-2^2) ?

The first derivative of (3x-2^2) is 6(3x-2)

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\frac{d}{d x} ((3 x - 2)^{2})

6 (3 x - 2)

Solution steps

\frac{d}{d x} ((3 x - 2)^{2})

Apply the chain rule:

2 (3 x - 2) \frac{d}{d x} (3 x - 2)

= 2 (3 x - 2) \frac{d}{d x} (3 x - 2)

\frac{d}{d x} (3 x - 2) = 3

= 2 (3 x - 2) \cdot 3

Simplify

= 6 (3 x - 2)

x \to 0 lim (ab s x)

\frac{\partial}{\partial v} (u + v^{2})

\frac{d y}{d x} + y = - e^{x}

x \to \frac{π}{2} lim (ln (cos (x)))

\int t^{2} \cdot cos (t) d t

What is the derivative of (3x-2^2) ?
The derivative of (3x-2^2) is 6(3x-2)
What is the first derivative of (3x-2^2) ?
The first derivative of (3x-2^2) is 6(3x-2)