What is the tangent of f(x)= 7/(sqrt(x)),\at x=1 ?

The tangent of f(x)= 7/(sqrt(x)),\at x=1 is y=-7/2 x+21/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 7/(sqrt(x)),\at x=1

tangent of

f (x) = \frac{7}{x}, at x = 1

y = - \frac{7}{2} x + \frac{21}{2}

Solution steps

Find the tangent point:

(1, 7)

Find the slope of

f (x) = \frac{7}{x} : \frac{df ( x )}{d x} = - \frac{7}{2 x ^{\frac{3}{2}}}

Compute the slope of

f (x) = \frac{7}{x}

x = 1 : m = - \frac{7}{2}

Find the line with slope m=

- \frac{7}{2}

and passing through

(1, 7) : y = - \frac{7}{2} x + \frac{21}{2}

y = - \frac{7}{2} x + \frac{21}{2}

\frac{\partial}{\partial u} (u + 2 v)

\frac{d}{d x} (x - 2 π)

y = x^{2} + 2 x - 2

y^{^{'}} = e^{9 y - x}

f (x) = x^{3}, at x = - 5

What is the tangent of f(x)= 7/(sqrt(x)),\at x=1 ?
The tangent of f(x)= 7/(sqrt(x)),\at x=1 is y=-7/2 x+21/2